(x^2)+(y^2)+(2x)-(4y)+3=0

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Solution for (x^2)+(y^2)+(2x)-(4y)+3=0 equation: 


Simplifying
(x2) + (y2) + (2x) + -1(4y) + 3 = 0
x2 + (y2) + (2x) + -1(4y) + 3 = 0
x2 + y2 + (2x) + -1(4y) + 3 = 0

Remove parenthesis around (4y)
x2 + y2 + (2x) + -1 * 4y + 3 = 0

Multiply -1 * 4
x2 + y2 + (2x) + -4y + 3 = 0

Reorder the terms:
3 + (2x) + x2 + -4y + y2 = 0

Solving
3 + (2x) + x2 + -4y + y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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